
RFLP / MstII test for Sickle-Cell Anemia
Sickle-cell Anemia is a molecular
disease caused by a mutation in
the
beta-globin gene. The
difference between the standard BA
allele and the sickle-cell BS allele
is a
single-nucleotide
substitution (A
T) in
the
second position of the sixth codon of this gene. The sequence of the
standard BA allele (CCTGAGG)
happens
to
correspond to an MstII
restriction
site (CCTNAGG), which is altered in the BS
allele
(CCTGGG).
The
beta-globin gene region includes two flanking MstII sites
(red
lines).
In the genetic test for the BS allele, total DNA from the individual tested is digested with MstII and run in a Southern Blot. The blot is hybridized with a probe specific for the beta-globin gene. If the standard BA allele is present, the probe sticks to the two small MstII fragments and produces two smaller bands. If the sickle-cell BS allele is present, the probe sticks to the single large fragment and produces one larger band. Thus, a standard AA homozygote shows the two-band pattern, a SS homozygote (with sickle-cell anemia) shows the one-band pattern, and an AS heterozygote (with sickle-cell trait) shows all three bands. The pattern of molecular expression is therefore described as co-dominant.
Important: this
particular
test depends on the coincidence
that the nucleotide
substitution
responsible for the sickle-cell allele happens to occur in such a way
as to create
an RFLP: the absence of the MstII site
does
not itself
cause
sickle-cell
anemia,
but is instead a genetic
marker for the allele.
Homework: Suppose
this
experiment
were done by amplifying
the
beta-globin gene by PCR, then cutting the product with MstII and
separating them by electrophoresis as above. How many bands would be expected in
the heterozygote? Explain.
Draw the expected result.