I. Proportion of total offspring contributed by each type of mating
| p2 'AA' | 2pq 'AB' | q2 'BB' | |
| p2 'AA' | p4 | 2p3q | p2q2 | 
| 2pq 'AB' | 2p3q | 4p2q2 | 2pq3 | 
| q2 'BB' | p2q2 | 2pq3 | q4 | 
II. Expected genotype ratios from each type of mating
| 'AA' | 'AB' | 'BB' | |
| 'AA' | all AA | 1/2 AA : 1/2 AB | all AB | 
| 'AB' | 1/2 AA : 1/2 AB | 1/4 AA : 1/2 AB : 1/4 BB | 1/2 AB : 1/2 BB | 
| 'BB' | all AB | 1/2 AB : 1/2 BB | all BB | 
III. Expected proportions
          of genotypes produced by each type of mating:
             multiply proportions in (I) by
        expectations in (II)
      
      
| p2 'AA' | 2pq 'AB' | q2 'BB' | |
| p2 'AA' | p4 AA | p3q AA + p3q AB | p2q2AB | 
| 2pq 'AB' | p3q AA + p3q AB | p2q2AA + 2p2q2 AB + p2q2 BB | pq3 AB + pq3BB | 
| q2 'BB' | p2q2AB | pq3 AB + pq3BB | q4 BB | 
f(AA) = p4 +p3q + p3q + p2q2 = (p2)(p2 + 2pq + q2) = p2
f(AB) = p3q + p2q2
        + p3q + 2p2q2 +p2q2
        + pq3 +
        pq3 
               
        = 2p3q + 4p2q2 + 2pq3 
        = (2pq)(p2 + 2pq + q2) = 2pq 
f(BB) = p2q2
        +pq3  + pq3 +q4
        = (q2)(p2 + 2pq + q2)
        = q2 
        
Conclusion:
                random matings among dioecious organisms
                produce the same genotype ratios as random union of
                  gametes in monoecious organisms
              
H HOMEWORK:
        Repeat the derivation above with allele frequencies d
        & e for alleles R & r,
        respectively.