Solutions to sample midterm Mendelian problems

1) Because the father has a, all of his daughters must inherit it. Because the mother is heterozygous, only half her sons will inherited a.

2) Because B is recessive to both the other alleles, only a BB genotype will be Brown.

3) A cross between two heterozygotes yields three genotypes (AA, Aa, & aa) at each locus. Four such loci would yield 3⁴ = 81 genotypic combinations, and so on.